Anyone have some words of wisdom on the true output current capability of the QSI decoder for Aristocraft locos?
The QSI current rating in their spec is shown as 2.7+ amps continuous and 3.0+ amps stall.
Not sure what QSI means by including a "+" sign - to me it means "more"...but how much more?
I have never seen that in a maximum current rating which this is supposed to be.
But putting that aside for a minute - this decoder is meant for Aristo locos with a plug-in decoder interface like the SD-45.
Now, on George Schreyer's website, the current he measured for the SD-45 under load exceeded the 2.7 amp rating as specified QSI which leads to the question - is the QSI decoder adequate to power an SD-45 under worst case conditions.
Looking at the 2.7 amp QSI spec, the answer seems to be "no", but when QSI was queried about that, they came back with an email that there is no problem up to 5 amps.
So why specify a maximum rating of 2.7 amps which is almost half of what QSI claims the decoder can handle - this doesn't make any sense to me at all.
Can anyone shed some light on any of this?
Thanks, Knut
The QSI current rating in their spec is shown as 2.7+ amps continuous and 3.0+ amps stall.
Not sure what QSI means by including a "+" sign - to me it means "more"...but how much more?
I have never seen that in a maximum current rating which this is supposed to be.
But putting that aside for a minute - this decoder is meant for Aristo locos with a plug-in decoder interface like the SD-45.
Now, on George Schreyer's website, the current he measured for the SD-45 under load exceeded the 2.7 amp rating as specified QSI which leads to the question - is the QSI decoder adequate to power an SD-45 under worst case conditions.
Looking at the 2.7 amp QSI spec, the answer seems to be "no", but when QSI was queried about that, they came back with an email that there is no problem up to 5 amps.
So why specify a maximum rating of 2.7 amps which is almost half of what QSI claims the decoder can handle - this doesn't make any sense to me at all.
Can anyone shed some light on any of this?
Thanks, Knut